C++17/20 - 使用<filesystem>确定文件是否可执行</filesystem>

Question

I want to know if there is a way to determine if a file in a directory is executable or not using the new C++17/20 #include <filesystem> . I do not want to use Boost. I know how this can be done with stat , st_mode and S_IXUSR but I haven't found a way to do it with pure C++17/20.

Answer 1

Check execution permissions , that is owner_exec , group_exec and other_exec attributes of the corresponding std::experimental::filesystem::permissions struct. Given a filename, it can be retrieved with

namespace fs = std::experimental::filesystem;

// ...

const auto permissions = fs::status("file.txt").permissions();

Check these according what you know about current user (is the current user owner of file, in file's user group).