该代码在 function 之外工作正常，但一旦进入内部，它就不起作用

Question

punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']


def strip_punctuation(word):

    for i in punctuation_chars:
        if i in word:
            word = word.replace(i, '')
            return word

print(strip_punctuation('GH.GH,GHGH:GHGH;GHGHG@'))

Answer 1

You're returning word after checking the first item, which means only the first punctuation mark ' would be stripped. Replace the function with this.

def strip_punctuation(word):
    for i in punctuation_chars:
        if i in word:
            word = word.replace(i, '')
    return word

Answer 2

It's because the return is inside of one of the loops, so you only get the first iteration done before printing the returned value. You'd need to put the return at the base of the function - out of the loops.

def strip_punctuation(word):
    for i in punctuation_chars:
        if i in word:
            word = word.replace(i, '')
    return word

Answer 3

When you call return, the function is exited. Therefore, the first time that i is in word and you replace it, you return the word and the function exits. If you were to complete the loop and then return the word, then it should work.

ie

def strip_punctuation(word):
    for i in punctuation_chars:
        if i in word:
           word = word.replace(i, '')
    return word