将元组中的元组转换为列表中的列表

Question

I am at the last step of my code where I am supposed to change my preferred laptops back to a list which are already in a descending order.

The tuples in the tuple list represent (ranking score, (name, company, screen size)) .

For example:

tuple_lst = [(20,('Elitebook','HP',13)),(10,('SurfacePro','Microsoft',13)),(5,('MacBook Air','Apple',13))]

My expected output:

[['Elitebook','HP',13],['SurfacePro','Microsoft',13],['MacBook Air','Apple',13]]

I have tried using list() and creating for loops but still failed to do so.

Any help is greatly appreciated.

Answer 1

Try this below using list comprehension:

tuple_lst = [(20,('Elitebook','HP',13)),(10,('SurfacePro','Microsoft',13)),(5,('MacBook Air','Apple',13))]

print([list(x[1]) for x in tuple_lst])

Answer 2

you do something like that

new_lst = [list(i[1]) for i in tuple_lst]

output

[['Elitebook', 'HP', 13],
 ['SurfacePro', 'Microsoft', 13],
 ['MacBook Air', 'Apple', 13]]

Answer 3

Try this:

tuple_lst = [(20,('Elitebook','HP',13)),(10,('SurfacePro','Microsoft',13)),(5,('MacBook Air','Apple',13))]
res = []

for tup in tuple_lst:
    res.append(list(tup[1]))

print(res)

Output will be:-

[['Elitebook','HP',13],['SurfacePro','Microsoft',13],['MacBook Air','Apple',13]]

Answer 4

A nice way is to use tuple unpacking:

>>> tuple_lst = [(20,('Elitebook','HP',13)),(10,('SurfacePro','Microsoft',13)),(5,('MacBook Air','Apple',13))]
>>> [list(y) for _, y in tuple_lst]
[['Elitebook', 'HP', 13], ['SurfacePro', 'Microsoft', 13], ['MacBook Air', 'Apple', 13]]

Answer 5

Here is the one line solution for your problem:

    tuple_lst = [(20,('Elitebook','HP',13)),(10,('SurfacePro','Microsoft',13)),(5,('MacBook Air','Apple',13))]
    tuple_lst = list(map(lambda x:list(x[1]),tuple_lst))
    print(tuple_lst)

Output: [['Elitebook', 'HP', 13], ['SurfacePro', 'Microsoft', 13], ['MacBook Air', 'Apple', 13]]