“UnboundLocalError：赋值前引用了局部变量‘score’”
[英]“UnboundLocalError: local variable 'score' referenced before assignment”
问题描述
Every time I run my program I get that message after answering the first question.
每次我运行我的程序时，我都会在回答第一个问题后收到该消息。 I don't understand why this keeps happening because I have created the score variable before everything, I don't see why there is an issue.我不明白为什么会一直发生这种情况，因为我在一切之前都创建了 score 变量，我不明白为什么会出现问题。 How do I solve this?我该如何解决这个问题？ This is my code:这是我的代码：
score = 0
name = input("Before we start, what would you like me to call you? : ")
def greeting():
print ("Welcome to your Math review quiz,",name)
print("You will have to answer 5 questions")
def quiz1():
q1 = int (input("5 + 5 : "))
if q1 == 10:
print("Correct")
score = score + 1
else :
print ("Incorrect")
q2 = int (input ("5 + 10 : "))
if q2 == 15 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q3 = int (input ("50 + 10 : "))
if q3 == 60 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q4 = int (input ("50 + 50 : "))
if q4 == 100 :
print("Correct")
score = score + 1
else :
print("Incorrect")
greeting()
quiz1()
4 个解决方案
解决方案1
1 2020-04-27 18:43:30
The scope of the variable score is not in quiz1 .变量score的 scope 不在quiz1中。 Therefore, I would pass it in, and return it as fit:因此，我会将其传入，并根据需要返回：
score = 0
name = input("Before we start, what would you like me to call you? : ")
def greeting():
print ("Welcome to your Math review quiz,",name)
print("You will have to answer 5 questions")
def quiz1(score):
q1 = int (input("5 + 5 : "))
if q1 == 10:
print("Correct")
score = score + 1
else :
print ("Incorrect")
q2 = int (input ("5 + 10 : "))
if q2 == 15 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q3 = int (input ("50 + 10 : "))
if q3 == 60 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q4 = int (input ("50 + 50 : "))
if q4 == 100 :
print("Correct")
score = score + 1
else :
print("Incorrect")
return score
greeting()
score = quiz1(score)
解决方案2
0 已采纳 2020-04-27 18:45:13
When you refer to a variable in a function definition (other than methods) python refers to the local veriable.当您在 function 定义（方法除外）中引用变量时，python 指的是本地可验证的。 You can edit score as a global variable with the global keyword.您可以使用global关键字将score编辑为全局变量。
score = 0
name = input("Before we start, what would you like me to call you? : ")
def greeting():
print ("Welcome to your Math review quiz,",name)
print("You will have to answer 5 questions")
def quiz1():
global score # add this line #
q1 = int (input("5 + 5 : "))
if q1 == 10:
print("Correct")
score = score + 1
else :
print ("Incorrect")
q2 = int (input ("5 + 10 : "))
if q2 == 15 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q3 = int (input ("50 + 10 : "))
if q3 == 60 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q4 = int (input ("50 + 50 : "))
if q4 == 100 :
print("Correct")
score = score + 1
else :
print("Incorrect")
greeting()
quiz1()
解决方案3
0 2020-04-27 18:45:56
make score global, add global score in the first line in the function. make score global，在 function 的第一行添加global score 。
解决方案4
-1 2020-04-27 18:47:03
This might help这可能会有所帮助
name = input("Before we start, what would you like me to call you? : ")
def greeting():
print ("Welcome to your Math review quiz,",name)
print("You will have to answer 5 questions")
def quiz1():
score = 0
q1 = int (input("5 + 5 : "))
if q1 == 10:
print("Correct")
score = score + 1
else :
print ("Incorrect")
q2 = int (input ("5 + 10 : "))
if q2 == 15 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q3 = int (input ("50 + 10 : "))
if q3 == 60 :
print("Correct")
score = score + 1
else :
print("Incorrect")
q4 = int (input ("50 + 50 : "))
if q4 == 100 :
print("Correct")
score = score + 1
else :
print("Incorrect")
greeting()
quiz1()
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