如何在 Python 中找到精确字符串匹配？

Question

I have list of words and want to check if string contains any of words from a list.

The code

String : "Business communication is often termed as the lifeblood of business concern justify this statement with an example"  
words = ['Fortnite', 'Digital Games',"Business","Technology","periodic table","med","ments"] 
for s in Q:
    s=re.sub('[^A-Za-z0-9]+'," ",s)

    print(s)
    for k in words:
        if k.lower() in s: 
            print(k)

Results: Business, med

Expected Output: Business

Answer 1

string = " " + inputString + " "
for word in words:
    if (" " + word + " ") in string:
        print(word)

Adding spaces in condition prevents problems with sub-words like med . First line allows first and last word to be found. If you need to deal with commas and periods then additional coding is required.

Answer 2

Why not:

#!/usr/bin/env python3
words = ['Fortnite', 'Digital Games',"Business","Technology","periodictable","med","ments"]
inputString = "Business communication is often termed as the lifeblood of business concern justify this statement with an example"
for word in words:
    for string in inputString.split(' '):
        if word == string:
            print(word)

It's computationally expensive, but it seems like it will do what you want it to do. Your regex string is nowhere near complicated enough to search for the words you want it to search for.

Answer 3

Given words and inputString :

words = ['Fortnite', 'Digital Games',"Business","Technology","periodictable","med","ments"]
inputString = "Business communication is often termed as the lifeblood of business concern justify this statement with an example"

you can create sets and take the intersection:

wset = set(words)
inpset = set(inputString.split())
print(wset & inpset)

which prints

{'Business'}