编程新手。 试图在 C 中编写一个程序，打印偶数直到 10。无法弄清楚逻辑错误

Question

#include <stdio.h>

main()
{
    int n=10;

    for(int a=n;a>=1;a++)  //for bringing out numbers from 1-10
    {
       int e=a%2; //int e to figure out if the number is even(divisible by 2)
       if(e==0)
        printf("%d\n",a); //printing the even numbers
    }
}

I am new to programming. Learning C. Here I am trying to make a program that prints even numbers till 10. Executing this code leads to endless even numbers starting from 10.

Can't seem to figure out the logic error here. Some help, please?

Answer 1

The logic for the for loop is not correct.

int n = 10;

for(int a = 0; a <= n; a++) {
    if(a%2==0){
        printf(a);
    }
}

Notice that this is stating at 0, because in CS almost all the time the count starts at 0.

Answer 2

Your loop will never end, it should be:

for(int a = 1; a <= 10; a++)

The entire program should be like that:

#include <stdio.h>

int main(void)
{ 
  for(int a = 1; a <= 10; a++)  //for bringing out numbers from 1-10    
    {
      int e = a % 2; //int e to figure out if the number is even(divisible by 2)
      if(e == 0)
        printf("%d\n", a); //printing the even numbers
    }
}

Output:

2
4
6
8
10