简体   繁体   English

mysqldump 用 php 导出单个表

[英]mysqldump with php to export a single table

I want to export one table from my database into a.sql file using mysqldump .我想使用mysqldump将我的数据库中的一张表导出到 .sql 文件中。

My code almost works:我的代码几乎可以工作:

$problem = ' --databases '.$db_name;

$cmd  = 'mysqldump';
$cmd .= ' --host='.$dbhost;
$cmd .= ' --user='.$dbuser;
$cmd .= ' --password='.$dbpass;
$cmd .= $problem;
$cmd .= ' > '.$filename;

shell_exec( $cmd.' '.$filename)

This code works fantastic, giving me a dump of the entire database into the file I've specified.这段代码效果很好,让我将整个数据库转储到我指定的文件中。

However: Now I only want to get one table dumped.但是:现在我只想丢一张桌子。

Let's modify the variable $problem :让我们修改变量$problem

option 1选项1

$problem  = ' --databases '.$db_name.' '.$table_name;

This still dumps the entire DB这仍然会转储整个数据库

option 2选项 2

$problem  = ' --databases '.$db_name;
$problem .= ' --tables '.$table_name;

option 3选项 3

$problem = ' --tables '.$table_name;

option 4选项 4

$problem = ' --tables '.$table_name.' '.$db_name;

option 5选项 5

$problem = ' '.$db_name.' '.$table_name;

Options 2 through 5 result in only some kind of header-like information being output into the file:选项 2 到 5 只导致文件中包含 output 的某种类似标题的信息:

-- MySQL dump 10.13  Distrib 5.5.58, for debian-linux-gnu (x86_64)
--
-- Host: mysql.mydomain.com    Database: [$db_name or $table_name]
-- ------------------------------------------------------
-- Server version   5.7.29-log

/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;
/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;
/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;
/*!40101 SET NAMES utf8 */;
/*!40103 SET @OLD_TIME_ZONE=@@TIME_ZONE */;
/*!40103 SET TIME_ZONE='+00:00' */;
/*!40014 SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0 */;
/*!40014 SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0 */;
/*!40101 SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO' */;
/*!40111 SET @OLD_SQL_NOTES=@@SQL_NOTES, SQL_NOTES=0 */;

Reading the Documentation hasn't given me any more insight...阅读文档并没有给我更多的洞察力......

The error was this:错误是这样的:

shell_exec( $cmd.' '.$filename);

has to be changed to必须改为

shell_exec( $cmd);

$filename had already been included into $cmd . $filename已经包含在$cmd中。

Once fixed, all the code works as expected.一旦修复,所有代码都按预期工作。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM