XPATH 通过 LXML 获取元素

Question

I am coding a Discord bot in a library for python, discord.py.

I don't need help with that but with scraping some info from the site.

    @commands.command(aliases=["rubyuserinfo"])
    async def rubyinfo(self, ctx, input):
        HEADERS = {
            'User-Agent' : 'Magic Browser'
        }

        url = f'https://rubyrealms.com/user/{input}/'

        async with aiohttp.request("GET", url, headers=HEADERS) as response:
            if response.status == 200:
                print("Site is working!")
                content = await response.text()
                soup = BeautifulSoup(content, "html.parser")
                page = requests.get(url)
                tree = html.fromstring(page.content)
                stuff = tree.xpath('/html/body/div[4]/div/div[3]/div[3]/div/div[2]/div[1]/div[2]/div/p')
                print(stuff)
            else:
                print(f"The request was invalid\nStatus code: {response.status}")

The website I am looking for is "https://rubyrealms.com/user/{input}/" where input is given while running h!rubyinfo USERNAME changing the link to https://rubyrealms.com/user/username/ .

On the website what I want to get is their BIO which has an XPATH of

"//*[@id="content-wrap"]/div[3]/div[3]/div/div[2]/div[1]/div[2]/div/p"

where the element is:

<p class="margin-none font-color">
Hey! My name is KOMKO190, you maybe know me from the forums or discord. I am a programmer, I know a bit of JavaScript, small portion of C++, Python and html/css. Mostly python. My user ID is 7364. ||| 5th owner of Space Helmet :) </p>

Any help on how I would scrape that? The only response my bot gives is "[]"

Answer 1

How about the following, using.select() method

from bs4 import BeautifulSoup

html = '<p class="margin-none font-color">Hey! My name is KOMKO190 :) </p>'

soup = BeautifulSoup(html, features="lxml")
element = soup.select('p.margin-none')[0]
print(element.text)

Prints out

Hey: My name is KOMKO190 :)

Answer 2

Change your XPath expression for a relative one:

from lxml import html
import requests
page = requests.get('https://www.rubyrealms.com/user/KOMKO190/')
tree = html.fromstring(page.content)
stuff = tree.xpath('normalize-space(//h3[.="Bio"]/following-sibling::p/text())')
print (stuff)

Output:

Hey! My name is KOMKO190, you maybe know me from the forums or discord. I am a programmer, I know a bit of JavaScript, small portion of C++, Python and html/css. Mostly python. My user ID is 7364. ||| 5th owner of Space Helmet :)

Answer 3

from bs4 import BeautifulSoup as bs

url = 'https://rubyrealms.com/user/username/'

session = requests.Session()
request = session.get(url=url)
if request.status_code == 200:
    soup = bs(request.text, 'lxml')
    print(soup.find('p', class_='margin-none font-color').text)
else:
    print(request.status_code)

You need install

pip install lxml
pip install beautifulsoup4