简体   繁体   English

从 Future 返回 object<list> 在 Flutter</list>

[英]Returning an object from Future<List> in Flutter

I'm struggle on parsing Future to object.我正在努力将 Future 解析为 object。 I want to retrieve the User data from Future<List<User>> to User object.我想从Future<List<User>>检索User数据到User object。 I can get the User data, but its still inside Future .我可以获取 User 数据,但它仍在Future中。

Future<List<User>> getDataUser(String name_,int id_) async{
    var datajson=await Network.getData("https://jsonplaceholder.typicode.com/users?username=$name_&id=$id_");
    final response=jsonDecode(datajson);
    List<User> fuser=response.map((r)=>User.fromJson(r)).toList();
    User user_=fuser.single;
    print('response: '+user_.name);
    return fuser;
}

EDIT: Network.getData is a Future<dynamic>编辑: Network.getDataFuture<dynamic>

When I call activeUser() , I want it to return an object ( User ).当我调用activeUser()时,我希望它返回一个 object ( User )。

User activeUser(Future<List<User>> fuser){
    List<User> user=fuser as List<User>;
    print('user: '+user.single.username);
    return user.single;
}

I always get this kind of error: type 'Future<List<User>>' is not a subtype of type 'List<User>' I'm avoiding using builder ( FutureBuilder or ListView.Builder or else) because I'm not going to make a list.我总是收到这种error: type 'Future<List<User>>' is not a subtype of type 'List<User>'我避免使用构建器FutureBuilderListView.Builder或其他),因为我不是要做一个清单。 It just a single map.它只是一个 map。 I want that Future<List<User>> is returning a User object.我希望Future<List<User>>返回User object。 The REST API I use, returning a list, not an object我使用的 REST API 返回一个列表,而不是 object

[
  {
    "id": 1,
    "name": "Leanne Graham",
    "username": "Bret",
    "email": "Sincere@april.biz",
    "address": {
      "street": "Kulas Light",
      "suite": "Apt. 556",
      "city": "Gwenborough",
      "zipcode": "92998-3874",
      "geo": {
        "lat": "-37.3159",
        "lng": "81.1496"
      }
    },
    "phone": "1-770-736-8031 x56442",
    "website": "hildegard.org",
    "company": {
      "name": "Romaguera-Crona",
      "catchPhrase": "Multi-layered client-server neural-net",
      "bs": "harness real-time e-markets"
    }
  }
]
  • Notice the rectangle bracket, its a list with one json map.注意矩形括号,它是一个包含一个 json map 的列表。

Try this:尝试这个:

var fName;
...

getDataUser(name, id).then((fuser){
    print('user: '+ fuser.single.username);
    this.fName = fuser.single;});

I've figured it out.我已经想通了。

I created a class ListUser to store the list that returned from a Future我创建了一个class ListUser来存储从Future返回的列表

class ListUser{
  final List<User> oneuser;

  DaftarUser({this.oneuser});

  factory ListUser.fromJson(List<dynamic> jsonuser){
    List userone=new List();
    userone=jsonuser.map((p)=>User.fromJson(p)).toList();

    return new ListUser(
      oneuser:userone
    );
  }
}


Then I call the class above to Future<List<User>>然后我将上面的 class 称为Future<List<User>>

Future<List<User>> getDataUser(String name_,int id_) async{
    var datajson=await Network.getData("https://jsonplaceholder.typicode.com/users?username=$name_&id=$id_");
    final response=jsonDecode(datajson);
    List<User> fuser=ListUser.fromJson(datajson).oneuser;
    // User user_=fuser.single;
    // print('response: '+user_.name);
    // those two line above are for seeing the value only, not too important
    return fuser;
}


The Function above will return a List<User> , so that I can change the activeUser function, like this:上面的 Function 会返回一个List<User> ,这样我就可以更改activeUser function,像这样:

User activeUser(List<User> fuser){
    User u=fuser.single;
    return u;
}

Now I can call that activeUser anywhere I need it.现在我可以在任何需要的地方调用activeUser

BTW, thanks for the help above.顺便说一句,感谢上面的帮助。 Cheers干杯

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM