[英]Writing custom deserializer for polymorphic type hierarchy Jackson
I'm experimenting with Jackson deserialization for inheritance in Java.我正在尝试对 Java 中的 inheritance 进行 Jackson 反序列化。 I've a base class:我有一个基础 class:
@Getter //Lombok @Getter
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "type", include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(value = {
@JsonSubTypes.Type(value=ClassA.class, name = "classA")
})
public abstract class BaseClass {
private List<String> fields;
@JsonCreator
public BaseClass(@JsonProperty("fields") final List<String> fields) {
this.fields = fields;
}
}
ClassA is also abstract ClassA 也是抽象的
@Getter
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, property = "typeA", include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(value = {
@JsonSubTypes.Type(value=SubClassA.class, name = "subclassA")
})
public abstract class ClassA extends BaseClass{
private String mode;
@JsonCreator
public ClassA(@JsonProperty("fields") final List<String> fields, @JsonProperty("mode") String mode) {
super(fields);
this.mode = mode;
}
}
My subClassA:我的子类A:
public class SubClassA extends ClassA {
private String dummyField;
public SubClassA(@JsonProperty("fields") final List<String> fields, @JsonProperty("mode") String mode,
@JsonProperty("dummyField") String dummyField) {
super(fields, mode);
this.dummyField = dummyField;
}
}
If I pass in a JSON of in the following form:如果我以以下形式传入 JSON :
{
"type": "classA",
"typeA": "subclassA",
"mode": "testingMode",
"fields": ["1", "2"],
"dummyField": "dummy"
}
I get an error Cannot construct instance of ClassA (no Creators, like default construct, exist): abstract types either need to be mapped to concrete types, have custom deserializer, or contain additional type information I came across this https://github.com/FasterXML/jackson-databind/issues/374 which says this is a known issue with Jackson.我收到一个错误无法构造 ClassA 的实例(没有创建者,如默认构造,存在):抽象类型要么需要映射到具体类型,要么具有自定义反序列化器,要么包含我遇到的此https://github 的其他类型信息。 com/FasterXML/jackson-databind/issues/374表示这是 Jackson 的已知问题。 How do I go about writing a customDeserializer for this.我该如何为此编写自定义解串器。
In classA I tried doing this:在 A 类中,我尝试这样做:
@JsonDeserialize(using = ClassADeserializer.class)
and ClassADeserializer is:和 ClassADeserializer 是:
public class ClassADeserializer extends StdDeserializer<ClassA> {
private final JsonDeserializer<?> defaultDeserializer;
public ClassADeserializer(JsonDeserializer<?> defaultDeserializer) {
super(ClassA.class);
this.defaultDeserializer = defaultDeserializer;
}
@Override public ClassA deserialize(final JsonParser jsonParser, final DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
return (ClassA) defaultDeserializer.deserialize(jsonParser, deserializationContext);
}
which obviously doesn't work.这显然是行不通的。 How do I go about writing a custom deserializer for this?如何为此编写自定义解串器?
You pass in json "type": "classA",
... That means jackson first try to create instance of ClassA
..During deserialization jackson search @JsonCreator
constructor first..If @JsonCreator
missing or can not call @JsonCreator
constructor then jackson create object with default constructor and call setter method... In your ClassA @JsonCreator
constructor with 2 arguments but jackson call with 3 arguments.. So its fail. You pass in json "type": "classA",
... That means jackson first try to create instance of ClassA
..During deserialization jackson search @JsonCreator
constructor first..If @JsonCreator
missing or can not call @JsonCreator
constructor then jackson create object with default constructor and call setter method... In your ClassA @JsonCreator
constructor with 2 arguments but jackson call with 3 arguments.. So its fail. then jackson call default constructor to create instance.然后 jackson 调用默认构造函数来创建实例。 but default constructor also missing.. thats why u get this error: Cannot construct instance of ClassA (no Creators, like default construct, exist)
..但是默认构造函数也丢失了..这就是为什么你会收到这个错误: Cannot construct instance of ClassA (no Creators, like default construct, exist)
..
As you want to deserialize to SubClassA
... You need to use @JsonCreator
in SubClassA...Then you need to use @JsonIgnoreProperties to ignore properties type
so that jackson create instance of SubClassA
instead of ClassA
....当您想反序列化为SubClassA
...您需要在 SubClassA 中使用@JsonCreator
...然后您需要使用 @JsonIgnoreProperties 来忽略属性type
,以便 jackson 创建SubClassA
的实例而不是ClassA
....
Try with below SubClassA
:尝试以下SubClassA
:
@Getter
@JsonIgnoreProperties(ignoreUnknown = true)
public class SubClassA extends ClassA {
private String dummyField;
@JsonCreator
public SubClassA(@JsonProperty("fields") final List<String> fields, @JsonProperty("mode") String mode,
@JsonProperty("dummyField") String dummyField) {
super(fields, mode);
this.dummyField = dummyField;
}
}
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