将包含不同长度列表的字典转换为 2 列 dataframe

Question

I have a dictionary like this one

my_dict = {0:[1,2],
           1:[1, 5, 100,120],
           2:[1, 89, 90, 1625, 98, 0, 10]}

I want to convert it to a data frame with just two columns like this one.

col1 col2
0   [1, 2]
1   [1, 5, 100,120]
2   [1, 89, 90, 1625, 98, 0, 10]

The second column includes a list of numbers. Any suggestions?

Answer 1

#Input dictionary
my_dict = {0:[1,2],
           1:[1, 5, 100,120],
           2:[1, 89, 90, 1625, 98, 0, 10]}

#Convert dictionary to dataframe
df = pd.DataFrame(my_dict.items(),columns=["col1","col2"])

print(df)

Output:

   col1                          col2
0     0                        [1, 2]
1     1              [1, 5, 100, 120]
2     2  [1, 89, 90, 1625, 98, 0, 10]

Answer 2

s=pd.Series(my_dict).reset_index()
Out[32]: 
   index                             0
0      0                        [1, 2]
1      1              [1, 5, 100, 120]
2      2  [1, 89, 90, 1625, 98, 0, 10]