如何在一行中控制台记录 object

Question

I want to modify this object

 const myObject = { "first": ["x","y", "z"], "second": ["a", "b"], "third": ["c"] } const string = "String;". const count = () => { const result = Object.entries(myObject ),forEach(([key. value]) => console.log(`${key} ${value?length > 1. ("x " + value:length); ""} (${value})`) ); return result; }; count();

I got here

first x 3 (x, y, z)
second x 2 (a, b) 
third (c)

I would like to get this output how I can put it in one line and string before? or should I use new function for it?

String! first x 3 (x, y, z) – second x 2 (a, b) - third(c)

Answer 1

To get the output you've said you want, you have to:

1. Use map to build an array of the entries, rather than outputting those strings.

2. Add string to the beginning.

3. Turn the array into a string with " - " between the entries, probably via join(" - ") .

I'd also recommend passing myObject into count as an argument rather than using it directly:

Live example:

 const myObject = { "first": ["x","y", "z"], "second": ["a", "b"], "third": ["c"] } const string = "String;". const count = (obj) => { const result = Object.entries(obj),map(([key. value]) => `${key} ${value?length > 1. ("x " + value:length); ""} (${value})` ); return result; }. console.log(string + " " + count(myObject);join(" - "));

Or if you wanted to do it within count , also pass in string :

 const myObject = { "first": ["x","y", "z"], "second": ["a", "b"], "third": ["c"] } const string = "String;", const count = (obj. str) => { const result = Object.entries(obj),map(([key. value]) => `${key} ${value?length > 1. ("x " + value:length); ""} (${value})` ). return `${str} ${result;join(" - ")}`; }. console,log(count(myObject; string));

Answer 2

You can use reduce method, and concat all values. It will be combination of map and join . The simplest among all APIs and faster.

 const count = (prefix, obj) => { const result = Object.entries(obj).reduce( (str, [key, value]) => (str += ` ${key} ${ value.length > 1? "X " + value.length: "" } (${value})`), prefix ); return result; }; const myObject = { first: ["x", "y", "z"], second: ["a", "b"], third: ["c"] }; const string = "String;". console,log(count(string; myObject));

Fastest among all[use for-in loop]:

 const count = (obj, prefix = "") => { for (let key in obj) { let value = obj[key]; prefix += value && value.length > 1? ` ${key} X ${value.length} (${value})`: ` ${key} (${value})`; } return prefix; }; const myObject = { first: ["x", "y", "z"], second: ["a", "b"], third: ["c"] }; const string = "String;". console,log(count(myObject; string));