如何在 function 调用期间使用中断将我的程序或 go 重置回主程序

Question

I've tried everything, and I am aware of the (void (code *)(void)) 0) ();, but as you know if you use it doesn't clear back the interrupts and you can't use it again. What is a workaround, and I have to use an external interrupt based on my HW. I've researched countless hours and looked through several of my books. I'm starting to believe it may not be possible? Code:

#include <reg51.h>
void delay();
int i,a;
sbit btn=P3^2;
sbit sw1=P0^1;
void mode1();
void reset (void);

void main()
{
    EA=1;
    EX0=1;
    ET0=1;
    EX1=1;

while(1){
    EA=1;
    EX0=1;
    ET0=1;
    EX1=1;
        if(sw1){
            mode1();
        }
        P1=0x01;
    }
}

void ex0() interrupt 0{
    if(!btn){
        //reset();
        Enable_Watchdog(); 
    }
}
/*
void reset (void){
(//(void (code *) (void)) 0x0000) ();
    (void (code *)(void)) 0) ();
}
    */

void mode1(){

    unsigned char repeat1 = 0x80;
    unsigned char repeat0 = 0x01;
    int g=0;
    int i =0;
    int j=0;
    EA=1;
    EX0=1;
    ET0=1;
    EX1=1;
        //how many leds it must go accross minus 1 since repeat 1 and 0

        while(sw1){
        EA=1;
        EX0=1;
        ET0=1;
        EX1=1;
        for(i =0; i <7; i++){
                P1=repeat1 >> i;
                delay();
            }
        for(j=0; j<7; j++){
            P1=repeat0 << j;
            delay();
        }
    }
}


void delay(){
    int k, j;
    for(k=0; k<0xff; k++)
        for(j=0;j<0xff;j++);

}

Answer 1

What is wrong with the watchdog enable you already have in the code in the question? It will work, but needs soem finessing:

void ex0() interrupt 0
{
    if(!btn)
    {
        EA = 0;   // Disable interrupts

        // Set watchdog counter and timeout 
        // to zero for immediate reset
        PCA0L    = 0x00;
        PCA0H    = 0x00;
        PCA0CPL2 = 0x00; 

        // Enable watchdog
        PCA0MD  |= 0x40;

        for(;;);  // Wait for reset
    }
}

A better solution if you are able is to connect a GPIO to the reset pin (with a pull-up) and reset it directly. On reset, the GPIO will tri-state, so release the reset - by virtue of the pull-up. You need to take care when initialising the GPIO that you do not immediately pull it low. Probably best to leave it as a tri-stated input until you actually want to effect a reset.