C 指向 function 的指针

Question

I have a this function which needs a Two Dimensional Integer Array:

void Add_Binary_To_Matrix(int (*qrMatrix)[21], int *binPtr,
        int x, int y, int count, int skipper, int direction)

And this array which is a one dimensional pointer array but I add memory to each row (which also makes it a two dimensional integer array right?):

int *qrCopy[currentVersion->height];
for (int i = 0; i < currentVersion->height; i++) 
    qrCopy[i] = malloc(currentVersion->height * sizeof(int));

So I've tried passing it a bunch of ways but none of them work:

Add_Binary_To_Matrix((int *)qrCopy, binPtr, 20, 20, 0, 0, 1);
Add_Binary_To_Matrix(qrCopy, binPtr, 20, 20, 0, 0, 1);
Add_Binary_To_Matrix(&((int *)qrCopy[0]), binPtr, 20, 20, 0, 0, 1);

but passing it like that doesn't seem to work so my question is how can I pass this array to the function?

Answer 1

It is impossible to pass the array to the function.

The type of int (*qrMatrix)[21] is a pointer to "21-element array of integers".

qrCopy is an array of pointers, so this cannnot be passed.

How to set the argument: Create an array and obtain pointer to that.

int array[21];
Add_Binary_To_Matrix(&array, binPtr, 20, 20, 0, 0, 1);