[英]How to print a pyramid in Python?
How to make a pyramid?如何制作金字塔?
I need to make a function, that prints a full pyramid.我需要制作一个 function,它可以打印一个完整的金字塔。
For example例如
(13 is the base width of the pyramid and 1 is the width of the top row.) (13 是金字塔的底边宽度,1 是顶行的宽度。)
pyramid(13, 1)
Result:结果:
.
.....
.........
.............
The step should be 4, so each row differs from the last row by 4 dots.步长应为 4,因此每行与最后一行相差 4 个点。
Edit:编辑:
This is what I have so far, but I only got the half of the pyramid and the base isn't what it's supposed to be.这是我到目前为止所拥有的,但我只得到了金字塔的一半,而底部不是它应该的样子。
def pyramid(a, b):
x = range(b, a+1, 4)
for i in x:
print(" "*(a-i) + "."*(i))
pyramid(17,1)
Try this:尝试这个:
def pyramid(a, b):
for i in range(b,a+1,4) :
print(str( " " *int((a-i)/2) )+ "."*(i)+ str( " " *int((a-i)/2) ))
Output: Output:
pyramid(17,1)
.
.....
.........
.............
.................
Here is my contribution, using -
character instead of blank space, for a better visualization:这是我的贡献,使用
-
字符而不是空格,以获得更好的可视化:
def pyramide(base, top, step=4):
dot = "."
for i in range(top, base+1, step):
print((dot*i).center(base, "-"))
pyramide(13,1)
Output Output
------.------
----.....----
--.........--
.............
# Function to demonstrate printing pattern triangle
def triangle(n):
# number of spaces
k = 2*n - 2
# outer loop to handle number of rows
for i in range(0, n):
# inner loop to handle number spaces
# values changing acc. to requirement
for j in range(0, k):
print(end=" ")
# decrementing k after each loop
k = k - 1
# inner loop to handle number of columns
# values changing acc. to outer loop
for j in range(0, i+1):
# printing stars
print("* ", end="")
# ending line after each row
print("\r")
# Driver Code
n = 5
triangle(n)
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