将 TSV 文件另存为 .txt 时，如何将其渲染为 JSON？

Question

I have a very large table saved as a text file that is imported to my company from an external source. The formatting in this file looks like it should be a.TSV. I need to find a way to get it into an Observable Collection. My thought was that I could use a Deserializer to automatically parse it out. That didnt work at all since I dont have any quotes saved in the whole document. Then I found this . The answer from giotskhada, seems like it would work, but its in Python, and I dont have a median file to save it into. Here is an example of the txt file:

id     FieldName1     FieldName2     FieldName3     FieldName4
1     test1           test3     test4
2           test2     test3     test4
3     test1     test2     test3     test4

and this is how I would like it to read out:

[ {"id":"1",
   "FieldName1":"test1",
   "FieldName2":"null",
   "FieldName3":"test3",
   "FieldName4":"test4"}
  },
  {"id":"2",
   "FieldName1":"null",
   "FieldName2":"test2",
   "FieldName3":"test3",
   "FieldName4":"test4"}
  },      
  {"id":"3",
   "FieldName1":"test1",
   "FieldName2":"test2",
   "FieldName3":"test3",
   "FieldName4":"test4"}
  ]

What can I do to make this happen in C#?

Answer 1

Well, if you open to use external library, Cinchoo ETL is one will help to achieve to handle large file in expected format.

install-package ChoETL.JSON

Here is sample working code

string tsv = @"id   FieldName1  FieldName2  FieldName3  FieldName4
1   test1       test3   test4
2       test2   test3   test4
3   test1   test2   test3   test4";

StringBuilder json = new StringBuilder();

using (var r = ChoTSVReader.LoadText(tsv)
    .WithFirstLineHeader()
    )
{
    using (var w = new ChoJSONWriter(json))
        w.Write(r);
}

Console.WriteLine(json.ToString());

Output:

[
 {
  "id": "1",
  "FieldName1": "test1",
  "FieldName2": null,
  "FieldName3": "test3",
  "FieldName4": "test4"
 },
 {
  "id": "2",
  "FieldName1": null,
  "FieldName2": "test2",
  "FieldName3": "test3",
  "FieldName4": "test4"
 },
 {
  "id": "3",
  "FieldName1": "test1",
  "FieldName2": "test2",
  "FieldName3": "test3",
  "FieldName4": "test4"
 }
]

Hope it helps.