Sed 命令：在目标字符串前后使用通配符搜索模式

Question

Content of sample.xml is like the one below.

<Name="com.name1.sample.date" level="ERROR"/>
<Name="com.name2.test" level="WARNING">
<Name="com.name3.type.yeah.trace" additivity="false" level="DEBUG">

I am trying to use sed and just replace the value of the "level paramater" on all lines. However, using (*) as wildcard is not working for pattern matching.

I'd like the output to be like the one below.

<Name="com.name1.sample.date" level="INFO"/>
<Name="com.name2.test" level="WARN">
<Name="com.name3.type.yeah.trace" additivity="false" level="UPDATE">

Basically: From this pattern *level="<pattern>"* To this pattern *level="<updated>"*

Where the * could be any pattern.

I did some research here and was able to make it work for wildcard at the beginning but not at the end so I am doing a special handling for each pattern that has a different ending. Below is my code.

sed 's|="'"$logger_type"'".*|="'"$logger_type"'" level="'"$update_check"'"/>|g'

Where $logger_type is the name being referenced, and its level should be updated to whatever the content of $update_check

Answer 1

Basically: From this pattern *level="<pattern>"* To this pattern *level="<updated>"*

Since your input is line-oriented, we can use " logger_type " as an address regexp to process only the lines matching the regular expression; therewith we can simplify the substitution pattern to only specify level="…" and leave other attributes (like additivity ) as they are.

sed /\"$logger_type'"/s/level="\w*"/level="'$update_check\"/ sample.xml