[英]DOMNode to DOMElement in php
I want to convert a DOMNode
object from a call to getElementsByTagName()
to a DOMElement
in order to access methods like getElementsByTagName()
on the child element.我想将
DOMNode
对象从对getElementsByTagName()
的调用转换为DOMElement
,以便访问子元素上的getElementsByTagName()
等方法。 In any other language, I would cast and it would be easy, but after some quick looking, PHP does not have object casting.在任何其他语言中,我会强制转换并且这很容易,但是经过快速查看后,PHP 没有对象转换。 So what I need to know is how to get a
DOMElement
object from a DOMNode
object.所以我需要知道的是如何从
DOMNode
对象中获取DOMElement
对象。
You don't need to cast anything, just call the method:您不需要强制转换任何内容,只需调用该方法:
$links = $dom->getElementsByTagName('a');
foreach ($links as $link) {
$spans = $link->getElementsByTagName('span');
}
And by the way, DOMElement
is a subclass of DOMNode
.顺便说一下,
DOMElement
是DOMNode
的子类。 If you were talking about a DOMNodeList
, then accessing the elements in such a list can be done, be either the method presented above, with a foreach()
loop, either by using the item()
method of DOMNodeList
:如果您正在谈论
DOMNodeList
,那么可以访问此类列表中的元素,可以使用上面介绍的方法,使用foreach()
循环,或者使用DOMNodeList
的item()
方法:
$link_0 = $dom->getElementsByTagName('a')->item(0);
This is what I use in my project to minimize IDE warning.这是我在我的项目中用来最小化 IDE 警告的方法。
/**
* Cast a DOMNode into a DOMElement
*/
function cast_e(DOMNode $node) : DOMElement {
if ($node) {
if ($node->nodeType === XML_ELEMENT_NODE) {
return $node;
}
}
return null;
}
You don't need to do any explicit typecasting, just check if your DOMNode object has a nodeType of XML_ELEMENT_NODE
.您不需要进行任何显式类型转换,只需检查您的 DOMNode 对象是否具有
XML_ELEMENT_NODE
的 nodeType 。
PHP will be perfectly happy with this. PHP 会对此非常满意。
If you use PHPLint to check your code you will notice that PHPLint complains about using getElementsByTagName
on a DOMNode object.如果您使用PHPLint检查您的代码,您会注意到 PHPLint 抱怨在 DOMNode 对象上使用
getElementsByTagName
。 To get around this you need to jump through the following hoop:要解决这个问题,您需要跳过以下环节:
/*.object.*/ $obj = $node;
$element = /*.(DOMElement).*/ $obj;
Then you will have a $element variable of the correct type and no complaints from PHPLint.然后您将拥有一个正确类型的 $element 变量并且没有来自 PHPLint 的抱怨。
I know this is mostly an annoying IDE problem.我知道这主要是一个烦人的 IDE 问题。
The reason is $DOMNodeList->item(0)
witch returns a DOMNode ( or at least the IDE thinks so ).原因是
$DOMNodeList->item(0)
女巫返回一个 DOMNode (或者至少 IDE 是这么认为的)。
To fix this you will have to Extract out the $DOMDocument->getElementsByTagName( $tagName )->item($index)
into a method of its own.要解决此问题,您必须将
$DOMDocument->getElementsByTagName( $tagName )->item($index)
提取到它自己的方法中。 In the DOCBlock you set the @return statement to DOMElement witch fixes the inspection problem.在 DOCBlock 中,您将 @return 语句设置为 DOMElement 以修复检查问题。
This Works at least in PHPStorm.这至少在 PHPStorm 中有效。
If anyone is looking for a more elegant solution in IntelliJ/PHPStorm .如果有人在IntelliJ/PHPStorm 中寻找更优雅的解决方案。 I managed to solve the issue like this:
我设法解决了这样的问题:
private function doSomething(DOMNode $child){
if(!$child instanceof DOMElement)
throw new Exception('DOMElement expected but got something else.');
$attr = $child->getAttribute('attr'); //recognized by PHPStorm now as DOMElement
/* and more code */
}
All my code corretly assumes DOMNode which is de super class of DOMElement but also DOMComment etc. When I need DOMElement to use getAttribute
for example, then I add above check.我所有的代码都正确地假设 DOMNode 是 DOMElement 的超类,但也是 DOMComment 等。当我需要 DOMElement 使用
getAttribute
,例如,我添加上面的检查。
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