在 sendTo 中对选定文件进行排序

Question

What's the way to sort a list of files, which is processed by a batch-file via sendTo-menu, eg:

myDir
  file_1.txt
  file_3.txt
  hello.world
  foo.bar

If I mark these files and call a batch file via sendTo-link to process those files, the order of the files seems to be random:

FOR %%A IN (%*) DO (set command=!command! %%A)
ECHO %command%

In some cases this shoud make no difference, but for merging for example, it does.

Something like using dir"*.sql ^| sort does not seem to work thus selected filenames are not considered.

Answer 1

@echo off
setlocal

rem Sort args stored if 1st argument is /sort_args.
if "%~1" == "/sort_args" goto :sort_args

rem Store all arguments in a named variable.
set args=%*

rem Process sorted arguments.
for /f "delims=" %%A in ('cmd /c "%~f0" /sort_args') do (
    echo %%A
)
exit /b 0


:sort_args

rem Abort if no arguments.
if not defined args exit /b 0

rem Sort arguments.
(for %%A in (%args%) do @echo %%A) | sort
exit /b 0

If the original arguments do not have /sort_args as an argument, then this will store the arguments in args . The for /f loop will run this code again to sort the original arguments and echo the arguments back to the for /f loop for processing.

Can change /sort_args to something more unique if wanted.