[英]Using generator to collate user inputs on multiple lines
I am trying to save some memory here - I am building a program where the user can input a (stacked) list of integers like:我正在尝试在这里保存一些 memory - 我正在构建一个程序,用户可以在其中输入(堆叠)整数列表,例如:
1
2
3
4
5
.
.
.
The below code works good!下面的代码效果很好!
input_list = []
while True:
try:
line = input()
except EOFError:
break
input_list.append(int(line))
print(input_list)
But I would now like to use some sort of generator expression to evaluate the list only when I need, and I almost (argh.) got there.但我现在想只在需要时使用某种生成器表达式来评估列表,而且我几乎(啊)到了那里。
This code works:此代码有效:
def prompt_user():
while True:
try:
line = input()
except EOFError:
print(line)
break
yield line
input_list = (int(line) for line in prompt_user())
print(list(input_list))
with one only quack: the last integer input by the user is always omitted.只有一个庸医:用户输入的最后一个 integer 总是被省略。 So for instance (the
^D
is me typing CTRL+D at the console from a pycharm debugger):例如(
^D
是我从 pycharm 调试器在控制台上键入 CTRL+D):
1
2
3
4^D
3 # ==> seems like after the EOF was detected the integer on the same
# line got completely discarded
[1, 2, 3]
I don't really know how to go further.我真的不知道如何进一步 go 。
Thanks to @chepner and to this other thread I reduced this whole logic to:感谢@chepner 和另一个线程,我将整个逻辑简化为:
import sys
N = input() # input returns the first element in our stacked input.
input_list = map(int, [N] + sys.stdin.readlines())
print(list(input_list))
leveraging the fact that sys.stdin
is already iterable!利用
sys.stdin
已经是可迭代的事实!
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