Python，如何以最优雅的方式将任意变量从 function 传递给 function？

Question

I have a dictionary vars = {'a': 1, 'b': 2} with key/value pairs. This dictionary can be extended with new variables in the future. I would like to call func1 with variables from vars dict. In func1 I will use zero or more variables from vars dict. If func1 has to call func2, I would like func2 to receive all variables from original vars dict. Func2 will use zero or more variables from vars dict.

Something like this:

def func1(**kwargs):
    print(f'func1 a = {a}, b is not important')
    return func2(**kwargs)

def func2(**kwargs):
    return f'func2 a = {a}, b = {b}, both variables are important'


vars = {'a' : 1, 'b' : 2}
print(func1(**vars))

But this doesn't work because kwargs is a dictionary. I can unpack variables at the beginning of the function if needed as:

a = kwargs['a']
b = kwargs['b']

but if a new variable "c" shows up in original vars dictionary, I will have to change these unpackings at the beginning of the each function. I could also set parameters def func1(a, b): and def func2(a, b): but i have to recreate kwargs dict in order to send it further down. Again, if a new variable "c" shows up, I will have to change signature of each function. I could also define func1 as bellow in order pass variable a further down:

def func1(a, kwargs):
    print(f'func1 a = {a}, b is not important')
    kwargs['a'] = a
    return func2(**kwargs)

Maybe to create an object and to set its properties as vars dict key/value pairs, and than send this object as function's parameter?

How to pass arbitrary variables from function to function in the most elegant way in this scenario?

Regards.

Answer 1

Why not just keep the variables in the dictionary and access them that way?

def func1(**kwargs):
    print(f"func1 a = {kwargs['a']}, b is not important")
    return func2(**kwargs)

def func2(**kwargs):
    return f"func2 a = {kwargs['a']}, b = {kwargs['b']}, both variables are important"


vars = {'a' : 1, 'b' : 2}
print(func1(**vars))