在 selenium python webdriver 中查找元素时出错

Question

I started with Selenium Webdriver and trying to open google.com and then click on button "Google search". I got the button element using chropath and below is my code

from selenium import webdriver
b = webdriver.Chrome()
b.get("http://google.com")
c = b.find_element_by_name("btnk")
c.click()

Getting error as

 raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"css selector","selector":"[name="btnk"]"}
  (Session info: chrome=81.0.4044.138)

Screenshot of chropath

Edit:

Below is the code to click on "I am feeling lucky"

from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium import webdriver
import time

b = webdriver.Chrome()
b.get("http://google.com")
timeout = 3
try:
    element_present = EC.presence_of_element_located((By.XPATH, "//div[@class='FPdoLc tfB0Bf']//input[@name='btnI']"))
    WebDriverWait(b, timeout).until(element_present)
    c = b.find_elements_by_xpath("//div[@class='FPdoLc tfB0Bf']//input[@name='btnI']")
    print("Value of c ", c)
    for i in c:
        print (i)
    c[0].click()
except TimeoutException:
    print("Timed out")

This is working but why c is a list.

Answer 1

I believe the problem is that you are not waiting for the view to be loaded before finding the element. You can use a Explicit Timeout to wait until btnK is in the view.

Use the WebDriverWait until presence_of_element_located . The timeout can be adjusted based on network conditions. It can be seen that in the html, there are two elements with btnK as their name. Although I do not know the reason for that, only one of them is visible, thus c[1] is used to click.

from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
import time

b = webdriver.Chrome()
b.get("http://google.com")
timeout = 3
try:
    element_present = EC.presence_of_element_located((By.NAME, 'btnK'))
    WebDriverWait(b, timeout).until(element_present)
    c = b.find_elements_by_name("btnK")
    c[1].click()
except TimeoutException:
    print("Timed out")

Answer 2

If you see DOM you will find two elements for the input button with name btnK and btnI Induce WebDriverWait () and wait for element_to_be_clickable () and following xpath.

from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

b = webdriver.Chrome()
b.get("http://google.com")
#Close the cookie if there..If not ignore
WebDriverWait(b,5).until(EC.element_to_be_clickable((By.XPATH,"//*[text()='Remind me later']"))).click()

#Click on Google Search
gsearch=WebDriverWait(b,5).until(EC.element_to_be_clickable((By.XPATH,"(//input[@name='btnK'])[last()]")))
gsearch.click()

Imluckuy=WebDriverWait(b,5).until(EC.element_to_be_clickable((By.XPATH,"(//input[@name='btnI'])[last()]")))
Imluckuy.click()