mysql 显示表格中的数据最大值和总和

Question

I have two tables and want to display the results for MAX of SUM total, group by name and month. only display maximum data from the total SUM results every month and group by name. this my table

table t2
+-------+-------+-------+
| month | total | id_t3 |
+-------+-------+-------+
|   1   |  15   |   1   |
|   1   |  20   |   2   |
|   1   |  50   |   1   |
|   2   |  40   |   2   |
|   2   |  20   |   3   |
|   2   |  20   |   1   |
|   3   |  10   |   3   |
+-------+-------+-------+

table t3
+----+--------+
| id |  name  |
+----+--------+
| 1  |  brian |
| 2  |  jessi |
| 3  |  redy  |
+----+---------

i want result 
+-------+---------------+
| month | total |  name |
+-------+---------------+
|   1   |  65   | brian |
|   2   |  40   | jessi |
|   3   |  10   | redy  |
+-------+---------------+

And this my query SQL

select t2.month, MAX(total), t3.name
from (
select t2.month, SUM(t2.total)as total, t3.name
from t2, t3
where t2.idt3 = t3.id
group by t2.month, t3.name
)result
group by t2.month, t3.name
order by total DESC

Answer 1

Hope it will solve your problem. group by month and name

select t2.month, SUM(t2.total), t3.name
from t2
join t3 on t2.id_t3 = t3.id
group by t2.month, t3.name
order by t2.total desc

Answer 2

If you want the maximum name per month, use window functions:

select month, name, total
from (select t2.month, t3.name, sum(t2.total) as total
             row_number() over (partition by t2.month order by sum(t2.total) desc) as seqnum
      from t2 join
           t3
           on t2.id_t3 = t3.id
      group by t2.month, t3.name
     ) t
where seqnum = 1
order by month;