如何在 style.js 文件中添加 php function ？

Question

This code perfect work if it writes in the same PHP file. But if I write a script in my style.js file and then call in PHP script src="style.js" then select option does not work. It looks like js file does not accept PHP code:

function account_number($sel_acc){
    $output = '';
    foreach($sel_acc as $row){
        $output .= '<option value="'.$row["NominalAccount"].'">'.$row["NominalAccount"].' ' .$row["NominalName"].'</option>';
    }
    return $output;
}

var count = $(".itemRow").length;
$(document).on('click', '#addRow', function(){
    count++;
    var htmlRows = '';
    htmlRows += '<tr>';
    htmlRows += '<td><select type="text" id="idAccounts'+count+'" name="idAccounts[]"><option value="4000">4000</option><?php echo account_number($sel_acc); ?></selected></td>';
    htmlRows += '</tr>';
    $("#inv_sale_detail").append(htmlRows);
});

Answer 1

The problem might be here:

?></selected></td>

The closing tag should be </select> At the end of that line. And the select input does not accept the attribute type Where you have written type="text"

Second: When you input <?php... ?> tags in any other file other than a php file that has the extension .php , it will be parsed as a string and will not produce the result as it would from a php file