如何将列表的子列表与同一列表中的其他列表的子列表进行比较

Question

I have a list of lists with each list having sublists for example something like the following:

mylist = [[['AB','CD'],['GH','EF'],['IJ','KL'],['']],[['CD','AB'],['EF','GH'],['KL','IJ'],['']],[['EF','GH'],['CD','AB'],['IJ','KL'],['']],...]

the number of lists are 1500 and each list of them has 16 sublists(the above is just an example). What I want to do is compare the sublist of the one list with the sublist of the other list , for all lists. To be more precise, I want to compare ['AB','CD'] with ['CD','AB'] and ['EF','GH'] and the first sublist of the rest of the lists . Same follows for the second sublist. I want to check if they have the same items, the order does not matter. So the ['AB','CD'] with ['CD','AB'] would be same. But then I need also to find which sublists contain the ['EF','GH'] and do some calculations when all same sublists are together. All in all, I want to check the 1st sublist of one list with the rest of the first sublists of each list and then do the same for each sublist(2nd,3rd,4th,..,15th). I thought of doing something like this

for i in range(0,len(mylist)):
        for j in range(i,len(mylist)):
            if mylist[i][j]==mylist[i + 1][j]:

but it doesn't seem to work when I do so. It gives me:

IndexError: list index out of range

I do not know if my approach is right. I tried to search and understand but I could not find something relevant.

all sublists are of same length.

Answer 1

You are tryng to acessa index out of the list range, when i is on the last position of the list. You do not need to go to the last position, it' enougth go to penultimate position and compare it with the last, like this:

for i in range(0,len(mylist)-1):
    for j in range(i,len(mylist[i])):
        if mylist[i][j]==mylist[i+1][j]:
            print('Found')