VS Code - 在模块模式下为 console_script 运行调试配置

Question

My setup.py has the following console_scripts as entry points:

entry_points={
        'console_scripts': ['script=myapp.app:do_something',
                            'script2=myapp.app:do_something2'],
    },

with the following structure

.
├── myapp
│   ├── __init__.py
│   ├── app.py
│   ├── mod.py
│   ├── mod2.py
│   └── submodules
│   ├── __init__.py
│   └── mod3.py
├── requirements.txt
└── setup.py

and app looking like

##my_app.app

def do_something():
  #do stuff
def do_something2():
  #do other stuff

How can I get VS code debug configuration to enter at these module attributes. I have this that can run the module if I use if __name__ == "__main__": do_something() but want seperate launch.json files depending on the console_scripts

##launch.json
{
  "configurations": [
    {
      "name": "Python: Module",
      "type": "python",
      "request": "launch",
      "cwd": "${workspaceFolder}",
      "module": "myapp.app",
      "args": ["--hello world"]
    }
  ]
}

Thought you might be able to do simlar with:

  "module": "myapp.app:do_something",

but alas:

No module named myapp.app:do_something

Answer 1

There currently isn't a way to make this work. At minimum you need a separate module per entry point or have a single module that took a command-line argument that then chose which function to call.