使用 C 语言创建具有给定字符串的结构名称

Question

I want to create a code that does something like this:

typedef struct {
  char name[1024];
  int age;
  char gender;
}person;

person Jacob = {.name = "Jacob", .age = 15, .gender = 'M'};

But I need to use the scanf option to get the variables, something like this:

typedef struct {
   char name[1024];
   int age;
   char gender;
}person;

char name_person[1024];
int age_person;
char gender_person;
scanf(" [:^\n],%d,%c",name_person,&age_person,&gender_person);

I would know if I can do something like this:

person name_person = {.name = name_person, .age = age_person, .gender = gender_person};

To do the same thing as the code above? I'm sorry if it sounds like a stupid question, I'm very new to C language.

Answer 1

For name you need to use c builtin func to make copies... the other field of your struct can be assigned straightforward

Answer 2

You can use scanf with struct like this.

typedef struct {
   char name[1024];
   int age;
   int sex;
}person;

person human;
scanf(" [:^\n],%d,%c",human.name,&human.age,&human.sex);

or you can use struct like this

person human;
char c;
int a;
float b;

scanf("%c %d %f",&c,&a,&b);

human.name=c;
human.age=a;
human.sex=b;

Answer 3

When using 'scanf' you need to match the format to the variable.

The scanf will deal with the name (char []), and age (int), but you will temporary variable to handle the conversion of the 'sex' attribute from char to int.

Also consider change to format - looks like the input is comma separated. If this is the case then'%[^,]' will work.

{
        // Good idea to initialize 'p'.
        person p = {} ;
        char sex ;

        scanf(" %[^,],%d,%c", p.name, &p.age, &sex) ;
        p.sex = sex ;
}