[英]Data is not display after insertion through Bootstrap modal with jquery ajax in php Mysqli
Data is not display after insert through bootstrap modal with ajax in php mysqli.在 php mysqli 中使用 ajax 通过引导模式插入后数据不显示。
jQuery Ajax code: jQuery Ajax 代码:
$(document).ready(function() {
fetch_data();
function fetch_data() {
var action = "fetch";
$.ajax({
url: 'action.php',
method: 'post',
data: {action: action},
success: function (data) {
$("#all_table_data").html(data);
}
});
}
});
function addData() {
var formData = new FormData($('#employee_insert_form')[0]);
formData.append('action', 'add');
$.ajax({
method: 'post',
url: 'action.php',
data: formData,
processData: false,
contentType: false,
cache: false,
success: function (response) {
$("#all_table_data").html(response);
$('#empInsert').modal('hide');
fetch_data();
}
});
}
Your PHP code never return anything to your view.您的 PHP 代码永远不会返回任何内容。 So try to echo result of select * from tbl_employee after the insertion
所以尝试在插入后从 tbl_employee 回显 select * 的结果
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.