[英]How to improve performance of iteration through a HashMap in Java?
Does anybody have any idea about how I could improve the performance of this method?有人知道如何提高这种方法的性能吗? Note that this.allActions is a hashmap with around half a million keys.
请注意,this.allActions 是一个 hashmap,具有大约 50 万个密钥。
Maybe there is a faster way of iterating through a HashMap that I don't know.也许有一种更快的方法来遍历我不知道的 HashMap。
public String get_random_legal_action(String stateJSON) {
Collections.shuffle(this.allActionsKeys);
boolean legal;
HashMap<String, Integer> state = new Gson().fromJson(stateJSON, this.stateType);
for (String action : this.allActionsKeys) {
legal = true;
for (Map.Entry<String, Integer> precondition : this.allActions.get(action).precondition.entrySet()) {
try {
if (!state.get(precondition.getKey()).equals(precondition.getValue())) {
legal = false;
break;
}
} catch (NullPointerException e) {
if (!this.immutableProps.contains(precondition.getKey())) {
legal = false;
break;
}
}
}
if (legal)
return action;
}
return null;
}
Convert the HashMap
to LinkedHashMap
to improve the performance,将
HashMap
转换为LinkedHashMap
以提高性能,
the complexity of Get O(1), Contains O(1) and Next O(1) Get O(1) 的复杂度,包含 O(1) 和 Next O(1)
, You can create custom Key class and update hashCode()
function , 您可以创建自定义密钥 class 并更新
hashCode()
function
Use it in like LinkedHashMap<Key, Integer>
像
LinkedHashMap<Key, Integer>
一样使用它
static class Key {
private static final int R = 256;
private static final long Q = longRandomPrime();
private String k;
public Key(String k) {
this.k = k;
}
public String key() {
return k;
}
@Override
public int hashCode() {
return Long.hashCode(hash());
}
@Override
public boolean equals(Object o) {
if (this == o)
return true;
if (o == null)
return false;
if (getClass() != o.getClass())
return false;
Key other = (Key) o;
return k.equals(other.k);
}
@Override
public String toString() {
return k;
}
private long hash() {
long h = 0;
for (int j = 0; j < k.length(); j++) {
h = (R * h + k.charAt(j)) % Q;
}
return h;
}
private static long longRandomPrime() {
BigInteger prime = BigInteger.probablePrime(31, new Random());
return prime.longValue();
}
}
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