getopts 命令不接受需要参数的多个选项

Question

I'm having problems with getopts command.

When I want to use an option that requires the SAME argument, it stops running the program after the first option that requires an argument (-i for example). So when I want it to take the options -id or -i -d it will stop running the while loop after the "-i" option is used and ignore the -d option.

How can I get the loop to continue and for the -d option to execute as well?

The format for the arguments passed can be: "-id argument" or "-i -d argument"

I'm using $p currently to grab the final argument to pass for each option currently. this is linux ubuntu shell in dash:

To make the code smaller and quicker to read:

for p do :; done

    echo arguments === $1 $2 $3 
    echo p = $p 
    while getopts ":hva:b:d:g:i:u:w:" opt; 
    do
        case "$opt" in

        i)
        checkdir $p
        fileinfo $p 
 ;;

        ***OTHER OPTIONS FOLLOW SIMILAR FORMAT***

        esac

    done

Answer 1

When I want to use an option that requires an argument, it stops running the program after the first option that requires an argument (-i for example). So when I want it to take the options -id or -i -d it will stop running the while loop after the "-i" option is used.

If you want it to take the options … -i -d , you have to (since each of them requires an argument ) supply an argument right after each option, eg … -i argument1 -d argument2 … .
With -id or -i -d the d or -d , respectively, is taken for the option's argument.