需要使用 python 删除列表中具有特定分隔符的单词

Question

Need to remove the word separating characters (such as , . - * ! and space ) from each of the word, present in list words. Store the obtained result again in the list words.

I can't seem to remove the whole word in my words list. Is there such a thing? I tried below code but it wont remove the words with above chars. Also, can I need to use list comprehension and strip func.

words=([s.strip(",.-*! ") for s in (Convert(setofStrings))])
print(words)

Answer 1

Try this:

b = ["aa-2", "bb-2"]
words = [x.split("-") for x in b]

output:

[['aa', '2'], ['bb', '2']]

That is if you want to split the words, if you just want to remove the characters you can use .replace()

Answer 2

strip() will only remove those characters from beginning or end of string. You need to either use translate() or for more complicated regular expression based substitution re.sub() .

Example of translate() using deletechars argument:

words = ['-foo.,', '!b*a-!r', 'ba*!,-z']
words = [s.translate(None, '-.!*,') for s in words]

and example of re.sub() :

import re

words = ['-foo.,', '!b*a-!r', 'ba*!,-z']
words = [re.sub(r'[-\.!\*,]', '', s) for s in words]

Output:

['foo', 'bar', 'baz']

Answer 3

As suggested you could use re.sub in combination with a list comprehension if your aim is to remove the characters from a list of strings.

import re
list_of_words = ['test.','cool!','wow ','y*,!']
result = [re.sub('[,\.\-\*\! ]', '', word) for word in list_of_words]