将元组列表转换为字典

Question

I am trying to convert my list of tuples 'L' into a dictionary. I am trying to write some code that will add element[5] to my value when the same key (in element[1]) is looped instead of replacing the value.

L = [('super mario land 2: 6 golden coins','GB',1992,'adventure','nintendo',11180000.0),
 ('sonic the hedgehog 2', 'GEN', 1992, 'platform', 'sega', 6020000.0),
 ("kirby's dream land", 'GB', 1992, 'platform', 'nintendo', 5130000.0),
 ("the legend of zelda: link's awakening",'GB',1992,'action','nintendo',3840000.0),
 ('mortal kombat', 'GEN', 1992, 'fighting', 'arena entertainment', 2670000.0)]


D = {}

for element in L:

    D[element[1]] = element[5]




Dictionary I want:
    D = { 'GB': 20150000.0,
          'GEN': 8690000 }

Answer 1

You can use a defaultdict for this:

from collections import defaultdict

L = [('super mario land 2: 6 golden coins','GB',1992,'adventure','nintendo',11180000.0),
 ('sonic the hedgehog 2', 'GEN', 1992, 'platform', 'sega', 6020000.0),
 ("kirby's dream land", 'GB', 1992, 'platform', 'nintendo', 5130000.0),
 ("the legend of zelda: link's awakening",'GB',1992,'action','nintendo',3840000.0),
 ('mortal kombat', 'GEN', 1992, 'fighting', 'arena entertainment', 2670000.0)]

D = defaultdict(float)

for element in L:
    D[element[1]] += element[5]
print(D)

Output as requested

Answer 2

D = {}
for element in L:
    if element[1] in D:
        D[element[1]] += element[5]
    else:
        D[element[1]] = element[5]

Answer 3

Maybe:

for element in L:
    if not element[1] in D.keys():
         D[element[1]] = element[5]
     else:
         D[element[1]] += element[5]

Answer 4

Only for fun, one line solution

L = [('super mario land 2: 6 golden coins','GB',1992,'adventure','nintendo',11180000.0), ('sonic the hedgehog 2', 'GEN', 1992, 'platform', 'sega', 6020000.0), ("kirby's dream land", 'GB', 1992, 'platform', 'nintendo', 5130000.0), ("the legend of zelda: link's awakening",'GB',1992,'action','nintendo',3840000.0), ('mortal kombat', 'GEN', 1992, 'fighting', 'arena entertainment', 2670000.0)]

from itertools import groupby
from operator import itemgetter
from functools import reduce
dict([(K,reduce(lambda x,y:x+y,[e[-1] for e in T])) for K,T in groupby(sorted(L,key=itemgetter(1)),itemgetter(1))])

you get,

{'GB': 20150000.0, 'GEN': 8690000.0}