[英]Trying to make function that returns mysql 'SELECT * FROM' results, ended up returning undefined
I'm trying to make a function that returns an array of stats from SQL 'SELECT * FROM', when I don't use a function to return it, it works, but I can't use that array outside of 'function(err, results)' I'm trying to make a function that returns an array of stats from SQL 'SELECT * FROM', when I don't use a function to return it, it works, but I can't use that array outside of 'function(错误,结果)'
con.query(`SELECT * FROM MemberPeniz WHERE memberId = '${memberID}'`, function(err, results) {
if(err) {
throw err;
}
console.log(results)
})
I tried this:我试过这个:
function checkTimeoutMEMBERid(memberID) {
con.query(`SELECT * FROM MemberPeniz WHERE memberId = '${memberID}'`, function(err, results) {
if(err) {
throw err;
}
return results
})
}
const result = checkTimeoutMEMBERid(message.author.id);
console.log(result)
but as I say it returns undefined no matter what id I pass in但正如我所说,无论我传入什么 id,它都会返回 undefined
This is because, you are returning results to callback which will not return to caller function.这是因为,您将结果返回给回调,而回调不会返回给调用者 function。 You can update function as,您可以将 function 更新为,
function checkTimeoutMEMBERid(memberId) {
return new Promise((resolve, reject) =>{
con.query(`SELECT * FROM MemberPeniz WHERE memberId = ?`,[memberId], (err, results) => {
if(err) {
return reject(err)
}
resolve(results)
})
})
}
checkTimeoutMEMBERid(message.author.id)
.then(result =>
{
console.log(result)
})
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