Skip_elements() function 使用 enumerate() function

Question

Try out the enumerate function for yourself in this quick exercise. Complete the skip_elements function to return every other element from the list, this time using the enumerate function to check if an element is on an even position or an odd position.

def skip_elements(elements):
# code goes here

return ___

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

I have no idea how to use enumerate for this. Please help.

Answer 1

def skip_elements(elements):
    # code goes here
    element = []
    for i, e in enumerate(elements):
        if i % 2 == 0:
            element.append(e)
    return element

-- OR

def skip_elements(elements):
# code goes here
    element = [e for i, e in enumerate(elements) if i % 2 == 0]
    return element

Answer 2

def skip_elements(elements):
# code goes here
elements = [v for i, v in enumerate(elements) if i % 2 == 0]

return elements

I hope this will help you

Answer 3

def skip_elements(elements):
    list=[]
    for index,element in enumerate(elements):
        if index%2==0:
            list.append('{}'.format(element))
    return list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"]))

print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach']))

Here is my output:

['a', 'c', 'e', 'g']

['Orange', 'Strawberry', 'Peach']

Answer 4

def skip_elements(elements):
    # code goes here
    list = []
    for index,element in enumerate(elements):
        if index % 2 == 0:
            list.insert(index, element) 
    return list 

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

Answer 5

def skip_elements(elements):
    list=[]
    # code goes here
    for index,element in enumerate(elements):
        if index%2==0:
            list.append(element)
        
    return list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

Answer 6

def skip_elements(elements):
    # Initialize variables
    new_list = []
    i = 0
    # Iterate through the list
    for i in range(len(elements)):
        # Does this element belong in the resulting list?
        if i % 2 == 0:
            # Add this element to the resulting list
            new_list.append(elements[i])
        # Increment i
        i += 1

    return new_list

Answer 7

def skip_elements(elements): # Initialize variables new_list = [] i = 0

# Iterate through the list
for i in range(len(elements)):
    # Does this element belong in the resulting list?
    if i % 2 == 0:
        # Add this element to the resulting list
        new_list.append(elements[i])


return new_list

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']3 print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach'] print(skip_elements([])) # Should be []

Answer 8

even_elements = []
for i, alpha in enumerate(elements):
    if i % 2 == 0:
        even_elements.append(alpha)
    i += 1
return even_elements

Answer 9

def skip_elements(elements):

    new_list = []
    for index, element in enumerate(elements):
        if index % 2 == 0:
            new_list += [element]
        index + 1
    return new_list

Answer 10

def skip_elements(elements): # code goes here l1=[] for index,item in enumerate(elements): if (index%2==0): l1.append("{}".format(item)) return l1

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g'] print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

Answer 11

def skip_elements(elements): # creating a blank list list2=[] for ind, ele in enumerate(elements): if ind == 0 or ind % 2 == 0: list2.append(elements[ind]) return list2

print(skip_elements(["a","b","c","d","e","f","g"])) # Should be ['a','c','e','g'] print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) #

Answer 12

Also, you can use this code:

def skip_elements(elements):
    for index, e in enumerate(elements):
        if index % 2 == 0:
            print("{} - {}".format(index + 1, e))

print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) # Should be ['a', 'c', 'e', 'g']
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach'])) # Should be ['Orange', 'Strawberry', 'Peach']

---

Output:
1 - a 
3 - c 
5 - e 
7 - g 
None 
1 - Orange 
3 - Strawberry 
5 - Peach 
None

Answer 13

def skip_elements(elements):
    # create an empty list to store values
    new_list =[]
    for index, word in enumerate(elements):   #iterate over index & element of given list
        if index % 2 == 0:     #check if index is odd/even
            new_list.append(word)        #appending EVEN element to new_list
    return new_list            #return new list


print(skip_elements(["a", "b", "c", "d", "e", "f", "g"]))
print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach']))

Give it a go. ✌

---

Also,

 def skip_elements(elements): new_list = [obj for indx, obj in enumerate(elements) if indx % 2 == 0] return new_list print(skip_elements(["a", "b", "c", "d", "e", "f", "g"])) print(skip_elements(['Orange', 'Pineapple', 'Strawberry', 'Kiwi', 'Peach']))

There's a shortcut too! XD