Spring 数据 JPA Select 不同的列可分页

Question

I'd like to select distinct records based on a column where not null and return a page. The following is throwing java.sql.SQLSyntaxErrorException: ORA-01791: not a SELECTed expression.

(If I can get this to work I'd like to select distinct by a few additional columns.)

@Query(value="SELECT DISTINCT pm.batchId from PrintManifest pm",
//            + "where pm.batchId is not null"
        countQuery = "select count(DISTINCT pm.batchId) from PrintManifest pm",
        nativeQuery = true
)
Page<PolicyPrintManifest> findDistinctBatchId(Pageable pageable);

I also tried with no luck:

Page<PolicyPrintManifest> findDistinctByBatchIdExists(Pageable pageable);

What's the right way to do this query?

Answer 1

Is PrintManifest name of the table or the entity. Remember that in native query, you have to use table name not entity name