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如何使用给定的文件路径执行 Python 中的 .EXE 文件?

[英]How to execute an .EXE file in Python with a given filepath?

I'm trying to write a bit of code to allow me to open up an exe file within Python, but I don't know the general way to make it properly.我正在尝试编写一些代码以允许我在 Python 中打开一个 exe 文件,但我不知道正确制作它的一般方法。 I would think that the code would look something like this:我认为代码看起来像这样:

exec(open("C:\\Users\\user\\AppData\\Local\\Programs\\file-folder\\file.exe").read())

but when I compile the code using Geany, it gives me an error saying UnicodeDecodeError: 'charmap' codec can't decode byte 0x90 in position 2: character maps to undefined但是当我使用 Geany 编译代码时,它给了我一个错误说 UnicodeDecodeError: 'charmap' codec can't decode byte 0x90 in position 2: character maps to undefined

I get the same error message when I try to write the file path with just one \ between each folder, but it gives me the same error in the compiler.当我尝试在每个文件夹之间仅使用一个 \ 编写文件路径时,我收到相同的错误消息,但它在编译器中给了我相同的错误。 Any help on this is greatly appreciated.非常感谢您对此的任何帮助。

you can use subprocess.call :您可以使用subprocess.call

import subprocess
subprocess.call(["fullPath\\yourExe.exe"])

well you need to import os in your code if you wanna execute external files如果你想执行外部文件,你需要在你的代码中导入 os

import os
os.startfile(""C:\\Users\\user\\AppData\\Local\\Programs\\file-folder\\file.exe"")

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