[英]How to assign a name to an object by pasting
Consider the data frame dat
:考虑数据框
dat
:
dat <- data.frame(Loc = c("NY","MA"),
ID = c(1:2),
Sex = c("M","F")
)
Pretending there were a lot more data to go with this, and multiple observations for each ID
, I want to fit a model and save it in an object called NYM1mod
, which to me would stand for "model for New York Male number 1" I can use: paste(dat[1,1], dat[1,3], dat[1,2],"mod", sep="")
to output what I want: [1] "NYM1mod"
But how can I do something like this and make the output the name of a new object?假装 go 有更多数据,并且每个
ID
有多个观察结果,我想拟合一个 model 并将其保存在一个名为NYM1mod
的 object 中,对我来说它代表“纽约男一号模特”我可以使用: paste(dat[1,1], dat[1,3], dat[1,2],"mod", sep="")
to output what I want: [1] "NYM1mod"
但如何才能我做这样的事情并使 output 成为新的 object 的名称? For example, why can you not assign the number 3 to the output "NYM1mod" like this?: paste(dat[1,1], dat[1,3], dat[1,2],"mod", sep="") <- 3
例如,为什么不能像这样将数字 3 分配给 output "NYM1mod"?:
paste(dat[1,1], dat[1,3], dat[1,2],"mod", sep="") <- 3
As commented, consider using a list instead of many separate objects.如评论所述,考虑使用列表而不是许多单独的对象。 Specifically, generalize your modeling process in a defined function. Iterate it with
lapply
to return a list of objects.具体来说,在定义的 function 中概括您的建模过程。使用
lapply
对其进行迭代以返回对象列表。 Then rename with setNames
to return a single, named list of objects, indexable for all.然后用
setNames
重命名以返回一个单一的、命名的对象列表,所有对象都可以索引。 some, or one item without flooding global environment with many, separate objects:一些或一个项目,而不会用许多单独的对象淹没全局环境:
proc_model <- function(...) {
# MODELING PROCESS
...
return(model)
}
model_list <- setNames(lapply(sequence_pass_as_params, proc_model),
paste0(dat$Loc, dat$Sex, dat$ID, "mod"))
# ALL MODELS
model_list
# SELECT MODELS
model_list$NYM1mod
model_list$MAF2mod
In fact, if I understand your needs consider by
(another sibling to apply family as object-oriented wrapper to tapply
) to pass subset data frames of Loc , ID , and Sex into your modeling function. Wrap process with tryCatch
for subsets that do not exist and/or yields modeling errors.事实上,如果我了解您的需求,请考虑
by
另一个将 family 作为面向对象的包装器应用到tapply
的兄弟)将Loc 、 ID和Sex的子集数据帧传递到您的建模中 function。使用tryCatch
包装进程不存在和/或产生建模错误。
# RECEIVE DATA FRAME AS PARAMETER
proc_model <- function(df) {
tryCatch({
# MODELING PROCESS
model <- lm(..., data = df)
}, error = function(e) return(NULL)
)
}
# BUILD MODEL LIST BY SUBSETS
model_list <- by(dat, dat[,c("Loc", "Sex", "ID"), proc_model)
# RENAME ELEMENTS IN LIST WITH UNIQUE NAMES
model_list <- setNames(model_list, unique(paste0(dat$Loc, dat$Sex, dat$ID, "mod")))
# REMOVE EMPTY MODELS (I.E., ITEMS THAT RETURN NULL)
model_list <- Filter(model_list, LENGTH)
# ALL MODELS
model_list
# SELECT MODELS
model_list$NYM1mod
model_list$MAF2mod
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