从字符串列表中，获取字典列表

Question

I have a list of strings which contains spanish-recipes´s ingredients and its quantities and I would like to get a list of dictionaries splitting every ingredient, unit and quantity.

This is the list:

ingredients=[
 '50',
 'ccs',
 'aceite',
 '1',
 'hoja',
 'laurel',
 '\n',
 '1',
 'cabeza',
 'ajos',
 '1',
 'vaso',
 'vino',
 '1,5',
 'kilos',
 'conejo',
 '\n',
...]

I would like to get a dict like this:

my_dic=[
{"name":"aceite" ,"qt":50 ,"unit": "ccs"},
{"name":"laurel" ,"qt":1 ,"unit": "hoja"},
{"name":"ajos" ,"qt":1 ,"unit": "cabeza"},
{"name":"vino" ,"qt":1 ,"unit": "vaso"},
{"name":"conejo" ,"qt":1,5 ,"unit": "kilos"}, 
...]

I have been trying things but it was all a disaster. Any ideas?

Thanks in advance!!

Answer 1

So first, you want to remove the newlines from your original list:

ingredients = [i for i in ingredients if i is not '\n']

Then, each ingredient name is every third element in the ingredients list starting from the third element. Likewise for the quantity and unit, starting from the second and first elements, respectively:

names = ingredients[2::3]
units = ingredients[1::3]
qts = ingredients[::3]

Then, iterate through these lists and construct the data structure you specified (which is not actually a dict but a list of dict s):

my_list = []
for i in range(len(names)):
    my_dict = {"name":names[i],"qt":qts[i],"unit":units[i]}
    my_list.append(my_dict)

There are a lot of ways to compress all of the above, but I have written it for comprehensibility.

Answer 2

How about:

ingredients = (list)(filter(lambda a: a != '\n', ingredients))
ing_organized = []

for i in range (0, len(ingredients) , 3):
    curr_dict = {"name": ingredients[i+2] ,"qt": ingredients[i] ,"unit": ingredients[i+1]}
    ing_organized.append(curr_dict) 

I just removed '\n' elements from the list as they didn't seem to have meaning.

Answer 3

This doesn't produce a dictionary, but it does give you the output that you specify in the question:

# Strip out the \n values (can possibly do this with a .strip() in the input stage)
ingredients = [value for value in ingredients if value != '\n']

labels = ['qt', 'unit', 'name']

my_dic = [dict(zip(labels, ingredients[i:i+3])) for i in range(0, len(ingredients), 3)]

my_dic contains:

[{'qt': '50', 'unit': 'ccs', 'name': 'aceite'},
 {'qt': '1', 'unit': 'hoja', 'name': 'laurel'},
 {'qt': '1', 'unit': 'cabeza', 'name': 'ajos'},
 {'qt': '1', 'unit': 'vaso', 'name': 'vino'},
 {'qt': '1,5', 'unit': 'kilos', 'name': 'conejo'}]

Answer 4

You can clean you list with filter to remove the \n characters and then zip() it together to collect your items together. This makes a quick two-liner:

l = filter(lambda w: w != '\n', ingredients)

result = [{'name': name, 'qt':qt, 'unit': unit} 
          for qt, unit, name  in zip(l, l, l)]

result:

[{'name': 'aceite', 'qt': '50', 'unit': 'ccs'},
 {'name': 'laurel', 'qt': '1', 'unit': 'hoja'},
 {'name': 'ajos', 'qt': '1', 'unit': 'cabeza'},
 {'name': 'vino', 'qt': '1', 'unit': 'vaso'},
 {'name': 'conejo', 'qt': '1,5', 'unit': 'kilos'}]