分页的第一个链接显示 CodeIgniter 中的 404 页

Question

I am working on pagination of category page. my route is

$route['category/(:any)/(:num)'] = 'public_controller/category/$1';

And url to go to category page is http://localhost/ecom/category/seats but it shows 404 error page. but when I give http://localhost/ecom/category/seats/1 it works fine and pagination also works fine second and third links are also working but when I click on 1 in pagination it shoes 404 error page. my controller code is

   public function category($cat_slug = null,$offset = null){
 $cat_id = $this->db->where('cat_slug',$cat_slug)->get('categories')->row_array();
 $config['base_url'] = base_url() .'category/'.$cat_slug;
    $config['total_rows'] = $this->db->where('cat_id',$cat_id['cat_id'])->count_all('products');
    $config['per_page'] = 4;
    $config['uri_segment'] = 3;
$config['use_page_numbers'] = TRUE;
    $config['full_tag_open'] = "<ul class='pagination'>";
    $config['full_tag_close'] ="</ul>";
    $config['num_tag_open'] = '<li>';
    $config['num_tag_close'] = '</li>';
    $config['cur_tag_open'] = "<li class='disabled'><li class='active'><a href='#'>";
    $config['cur_tag_close'] = "<span class='sr-only'></span></a></li>";
    $config['next_tag_open'] = "<li>";
    $config['next_tagl_close'] = "</li>";
    $config['prev_tag_open'] = "<li>";
    $config['prev_tagl_close'] = "</li>";
    $config['first_tag_open'] = "<li>";
    $config['first_tagl_close'] = "</li>";
    $config['last_tag_open'] = "<li>";
    $config['last_tagl_close'] = "</li>";

    $this->pagination->initialize($config);
 $data['products'] = $this->public_model->category_page($cat_slug,$config['per_page'],$offset);
 $id['cat_slug'] = $cat_slug;
 $this->load->view('public_temp/header1');
 $this->load->view('public_temp/left1',$id);
 $this->load->view('public/category',$data);
 $this->load->view('public_temp/footer1');
}

What can I try to resolve this?

Answer 1

It shows because your router expect 2 parameter but you are giving 1 parameter seats

Define your route this way

$route['category/(:any)/(:num)'] = 'public_controller/category/$1/$2';

Now call your route http://localhost/ecom/category/seats/0 for category page http://localhost/ecom/category/seats/1 for first pagination

if you want to separate your category route Define two route one for category page and other for category pagination

For category page

$route['category/(:any)'] = 'public_controller/category/$1';

For category pagination

$route['category/(:any)/(:num)'] = 'public_controller/category/$1/$2';

Answer 2

So, I created a demo for your problem and this is what worked for me ↓↓

$route['category']               = 'my_controller/category';       // this route handles all the requests without any additional segments
$route['category/(:any)']        = 'my_controller/category/$1';    // this route handles the requests when only one segment is present
$route['category/(:any)/(:num)'] = 'my_controller/category/$1/$2'; // this route handles the requests when there are two segments(2nd parameter being a number)

This is possible because

Routes will run in the order they are defined. Higher routes will always take precedence over lower ones.( Reference )

I also found a similar question you might wanna take a look at.

Hope this resolves your issue.