SQL - 将 BIGINT(20) 转换为日期时间数据类型

Question

In mysql workbench, I have an id column in my table with bigint as its data type:在 mysql 工作台中，我的表中有一个 id 列，其数据类型为 bigint：

id BIGINT(20)

This column holds the datetime as a bigint.此列将日期时间保存为 bigint。

To clarify more, the column holds a value such as:为了更清楚地说明，该列包含一个值，例如：

20190529230339

I need to convert it into a datetime data type to be presented as:我需要将其转换为日期时间数据类型以显示为：

2019-05-29 23:03:39

Answer 1

You could use STR_TO_DATE , after first casting the bigint number to text:在首先将 bigint 数字转换为文本后，您可以使用STR_TO_DATE ：

SELECT
    field,
    STR_TO_DATE(CAST(field AS CHAR(14)), '%Y%m%d%H%i%s') AS field_datetime
FROM yourTable;

Demo 演示

Answer 2

STR_TO_DATE will do the trick: STR_TO_DATE 可以解决问题：

SELECT CONVERT(STR_TO_DATE('20130101 1130','%Y%m%d %h%i'),DATETIME); SELECT CONVERT(STR_TO_DATE('20130101 1130','%Y%m%d %h%i'),DATETIME);

I used Convert instead of Cast我使用 Convert 而不是 Cast

2013-01-01 11:30:00 2013-01-01 11:30:00