如何用 JavaScript 中的正则表达式捕获组替换整个字符串？

Question

In a NodeJS application, I have a phone number field in my data that displays any number of phone numbers, one after another, in the same string:

\n\n \n (555) 555-5555 (Main)\n\n, \n\n \n (777) 777-777 (Domestic Fax)\n\n

I want to extract only the 'Main' phone number and convert it to the format 555-555-5555 , that is whatever the Main number is. Basically I just want to extract whatever number precedes 'Main' and make it more legible (replacing the space with the '-')

I got as far as finding the correct regex string

const phoneRegex = /^[ \\n]*\(([0-9]{3})\)( )([0-9]{3}-[0-9]{4}) \(Main\).*$/

but when I try to replace the string, it doesn't work

foo.phone =foo.phone.replace(phoneRegex,'$1-$3')

I keep getting the entire matched portion -- that is all the \n's and everything up to and including '(Main)'

I have searched for how to replace the entire string with the capture groups, but I haven't figured it out.

Answer 1

Would that work for you?

 const str = `\n\n \n (555) 555-5555 (Main)\n\n, \n\n \n (777) 777-777 (Domestic Fax)\n\n`, [,code, phone] = str.match(/\((\d{3})\)\s(\d{3}\-\d{4})\s\(Main\)/), result = `${code}-${phone}` console.log(result)

Answer 2

You may use

 var s = "\\n\\n \\n (555) 555-5555 (Main)\\n\\n, \\n\\n \\n (777) 777-777 (Domestic Fax)\\n\\n"; console.log( s.replace(/^[^]*?\((\d{3})\)\s*(\d+)-(\d+)\s*\(Main\)[^]*/, '$1-$2-$3') );

Details

• ^ - start of string
• [^]*? - any 0 or more chars, as few as possible
• \( - a (
• (\d{3}) - Group 1: three digits
• \) - a ) char
• \s* - 0+ whitespaces
• (\d+) - Group 2: one or more digits
• - - a hyphen
• (\d+) - Group 3: one or more digits
• \s* - 0+ whitespaces
• \(Main\) - a (Main) string
• [^]* - the rest of the string.

See the regex demo .