如何在输入 null 输入时跳出循环

Question

The following program is to display the word with maximum number of vowels.But it does not work until i have given 10 variables as input even though it is supposed to end after giving a null input.How can I fix this problem ( I already tried using different inputs like "." and " ")

**

import java.util.*;
public class hw1{
public static void main(String args[]){
        Scanner sc=new Scanner(System.in);

        String w,temp="";
        int c=0,max=0;

        for(int i=0;i<10;i++)
        {
            w=sc.next();
            w=w.toUpperCase();
            if(w.equals(""))
            break;

            for(int j=0;j<w.length();j++)
            {
                if(w.charAt(j)=='A'||w.charAt(j)=='E'||w.charAt(j)=='I'||w.charAt(j)=='O'||w.charAt(j)=='U')
                c++;
            }
            max=Math.max(max,c);
            if(max==c)
            temp=w;
            c=0;
        }

        System.out.println(temp);
    }
}

**

Answer 1

sc.next()

does not trigger if you give empty input (or press enter). For allowing your exit condition to work you should use

w=sc.nextLine();

After that, if you hit enter, the for is broken and the app prints the result