[英]Python groupby itertools method
I am new to python programing.I am unable to create the following code:我是 python 编程的新手。我无法创建以下代码:
Define a function even_or_odd, which takes an integer as input and returns the string even and odd, if the given number is even and odd respectively.定义一个 function even_or_odd,它将 integer 作为输入,如果给定的数字分别是偶数和奇数,则返回字符串偶数和奇数。 Categorise the numbers of list n = [10, 14, 16, 22, 9, 3, 37] into two groups namely even and odd based on above defined function.
根据上面定义的 function 将列表 n = [10, 14, 16, 22, 9, 3, 37] 的数字分为两组,即偶数和奇数。 Hint: Use groupby method of itertools module.
提示:使用 itertools 模块的 groupby 方法。 Iterate over the obtained groupby object and print it's group name and list of elements associated with a group.
遍历获得的 groupby object 并打印它的组名和与组关联的元素列表。
I have tried below code:我试过下面的代码:
import itertools
def even_or_odd(n):
if n%2==0:
return 'even'
else:
return 'odd'
group=[]
uniquekeys=[]
n = [10, 14, 16, 22, 9, 3 , 37]
for k,g in itertools.groupby(n, even_or_odd(n)):
groups.append(list(g))
uniquekeys.append(k)
It is giving "TypeError: unsupported operand type(s) for %: 'list' and 'int' "
When you try to pass itertools.groupby
even_or_odd
you call it with n
.当您尝试通过
itertools.groupby
even_or_odd
时,您使用n
调用它。 even_or_odd
takes an int
, but n
is a list. even_or_odd
需要一个int
,但n
是一个列表。 Just change it to itertools.groupby(n, even_or_odd)
只需将其更改为
itertools.groupby(n, even_or_odd)
Also you append to groups
when I think you mean group
.当我认为您的意思是
group
groups
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