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访问从模板参数包实例化的 class 实现

[英]Access class implementation instanciated from template parameter packs

I would like to instantiate all States in the MachineT as a shared_ptr<T> then access them by typename.我想将MachineT中的所有States实例化为shared_ptr<T>然后通过类型名访问它们。

In the following code, it refers to the instantiation (MachineT constructor) and a way to access the states (get function).在下面的代码中,它指的是实例化(MachineT 构造函数)和访问状态的方法(get 函数)。

Is there any hashmap trick or a way to store in the class an "Index" information such as StateA::Index ?是否有任何 hashmap 技巧或方法可以在 class 中存储“索引”信息,例如StateA::Index

#include <memory>
#include <vector>

template <typename... States>
class MachineT {
 public:
  MachineT() {
    states_.resize(sizeof...(States));
    for (unsigned i = 0; i < states_.size(); ++i) {
      // Instanciate states
      // states_[i].reset(new decltype(State[i])());
    }
  }
  ~MachineT() {}

  class State {
    State(int state_id) : state_id_(state_id) {}
    const size_t state_id_;
  };

  template<typename T>
  std::shared_ptr<T> get() {
    // Retrun the shared_ptr to the State
  }

  std::vector<std::shared_ptr<State>> states_;
};

struct StateA;  // Forward declaration
struct StateB;
using StateMachine = MachineT<StateA, StateB>;

class StateA : StateMachine::State {};
class StateB : StateMachine::State {};

int main(int argc, char const* argv[]) {
  StateMachine sm;

  std::shared_ptr<StateA> state_a = sm.get<StateA>();
  return 0;
}

It's perfectly doable.这是完全可行的。 Here's how to do it in C++14:以下是在 C++14 中的操作方法:

#include <memory>
#include <tuple>

template <typename... States>
class MachineT {
 public:
  MachineT()
   : states_{
    std::make_shared<States>()...
  } {
  }
  ~MachineT() {}

  template<typename T>
  std::shared_ptr<T> get() {
      return std::get<std::shared_ptr<T>>(states_);
  }

  std::tuple<std::shared_ptr<States>...> states_;
};

struct State1 {};

int main() {

    MachineT<State1> a;
    a.get<State1>();
}

Equivalent of std::get can be implemented with C++11 tools可以使用 C++11 工具实现等效的std::get

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