如何使用 SQLAlchemy 创建“ORDER BY Column = 'Value'”查询

Question

I am new to SQLAlchemy & wanted to create an SQLAlchemy query equivalent to "order by exact match first". Below is the SQL:

select word from dictionary where word like '%Time%' order by (word = 'Time') desc;

This is my SQLAlchemy equivalent.

Dictionary.query.with_entities ( Dictionary.word )
.filter(Dictionary.word.like("%{}%".format("Time")))
.order_by(Dictionary.word == "Time")

But it throws an error at "order_by": SyntaxError: keyword can't be an expression. How to solve it?

Answer 1

Solved it.

from sqlalchemy.sql import func

.order_by(Dictionary.word == q,func.length(Dictionary.word))