[英]How I can output a constant text in struct when call cout?
I have this struct:我有这个结构:
struct sample {
int x;
};
and then I have this overload of operator<<:然后我有这个运算符<<的重载:
std::ostream &operator<<(const std::ostream &os, const sample &s) {
if (s.x == 0)
return os << "zero";
else
return os << "not zero";
}
main:主要的:
int main() {
sample sam;
sam.x = 0;
std::cout << sam << std::endl;
sam.x = 1;
std::cout << sam << std::endl;
return 0;
}
But the compiler gives me this error: Complile Error但是编译器给了我这个错误:编译错误
What can I do?我能做些什么?
You are right except for a small error in your operator signature:你是对的,除了你的操作员签名中有一个小错误:
std::ostream &operator<<(const std::ostream &os, const sample &s)
// ^^^^^ Problem
You mark the output stream as const
but then modify it inside the function:您将 output stream 标记为const
,然后在 function 中对其进行修改:
os << "zero";
and和
os << "not zero";
Because因为
std::basic_ostream<CharT,Traits>::operator<<
is not const
. std::basic_ostream<CharT,Traits>::operator<<
不是const
。
So, remove that const
and the code will work.因此,删除该const
并且代码将起作用。
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