Bash/Linux - 比较脚本中的十进制数字，来自 a.csv 列的数据

Question

I am trying to compare the decimal numbers in a column one by one. These comparisons are made with respect to constants.

I want to count the number of times the condition is true. But this part is ok.

The file with the data is a csv separated by ";"and the decimals are separated by a "."

I have the following code, but I have not achieved anything.

fixed_acidity_filter=$(awk 'BEGIN{FS=";"} {if($1>0 && $1<15) ]{print}}' winequality-white_sincabecera.csv | wc -l)

Can anyone help me?

Answer 1

# concept
echo -e "20\n10\n18\n15\n13\n21" | awk '{if($1>0 && $1<15) print $1}'
# your code
echo -e "20;10\n10;10\n18;10\n15;10\n13;10\n21;10" | awk 'BEGIN{FS=";"} {if($1>0 && $1<15) print $1}' | wc -l