正则表达式 python 中的多个匹配词

Question

Desired Output The requirement is to pull the exactly next word after the search word and write to the MODEL column. To pull features, we have only one word ie. FEATURE and write the corresponding feature to its model. Some models may not have features.

Models will be alphanumeric in nature and features can be single alphabet or an alphanumeric word.

Attaching Image of the desired output.

Answer 1

Code:

STRING-1 = "YOU POSSESS PRODUCT CAR1 HAVING FEATURE O. PART CAR2 HAVING FEATURE Z. SPECIFICATION CAR3 HAVING FEATURE D."

STRING-2 = "YOU POSSESS PRODUCT CAR4 HAVING FEATURE O. PART CAR5 HAVING FEATURE Z."

STRING-3 = "YOU POSSESS PRODUCT CAR6."

search_words = [
"PRODUCT",
"PART",
"SPECIFICATION"
]

MODEL = []

for search_word in search_words:
    MODEL.append(STRING-1.split(search_word, 1)[1].split()[0])
    MODEL.append(STRING-2.split(search_word, 1)[1].split()[0])
    MODEL.append(STRING-3.split(search_word, 1)[1].split()[0])
print(MODEL)

Output:

['CAR1', 'CAR2', 'CAR3', 'CAR4', 'CAR5', 'CAR6']

Answer 2

Try

>>> import re
>>>
>>> rx = re.compile( r"(?i)(?:PRODUCT|PART|SPECIFICATION)\s+(\w+)(?:\s+HAVING\s+FEATURE\s+(\w+))?" )
>>>
>>> input = '''
... Sample Input String-1: YOU POSSESS PRODUCT CAR1 HAVING FEATURE O. PART CAR2 HAVING FEATURE Z. SPECIFICATION CAR3 HAVING FEATURE D.
... Sample Input String-2: YOU POSSESS PRODUCT CAR4 HAVING FEATURE O. PART CAR5.
... Sample Input String-3: YOU POSSESS PRODUCT CAR6 HAVING FEATURE G.
... '''
>>>
>>> rx.findall(input)
[('CAR1', 'O'), ('CAR2', 'Z'), ('CAR3', 'D'), ('CAR4', 'O'), ('CAR5', ''), ('CAR6', 'G')]

demo