子集 dataframe 基于 R 中列内因子水平的分层偏好

Question

I have a dataframe which I would like to subset based on hierarchical preference of factor levels within a column. With following example I want to show, that per level of "ID" I want to select only one "method". Specifically, if possible keeping CACL, if CACL doesn't exist for this level, then subset for "KCL" and if that doesn't exist, then subset for "H2O".

ID<-c(1,1,1,2,2,3)
method<-c("CACL","KCL","H2O","H2O","KCL","H2O")
df1<-data.frame(ID,method)

  ID  method
1  1    CACL
2  1     KCL
3  1     H2O
4  2     H2O
5  2     KCL
6  3     H2O

ID<-c(1,2,3)
method<-c("CACL","KCL","H2O")
df2<-data.frame(ID,method)

  ID  method
1  1    CACL
2  2     KCL
3  3     H2O

I have done something similar subsetting by selecting a minimum number within a level, but am not able to adapt it. Am wondering whether I should use ifelse here too?

#if present, choose rows containing "number" 2 instead of 1 (this column contained only the two numbers 1 and 2)

library(dplyr)
new<-df %>%
group_by(col1,col2,col3) %>%
summarize(number = ifelse(any(number > 1), min(number[number>1]),1))
dfnew<-merge(new,df,by=c("colxyz","number"),all.x=T)

Answer 1

You can use order with match and then simply !duplicated :

df1 <- df1[order(match(df1$method, c("CACL","KCL","H2O"))),]
df1[!duplicated(df1$ID),]
#  ID method
#1  1   CACL
#5  2    KCL
#6  3    H2O

#Variant not changing df1
i <- order(match(df1$method, c("CACL","KCL","H2O")))
df1[i[!duplicated(df1$ID[i])],]

Answer 2

An option using dplyr :

df1 %>% 
  mutate(preference = match(method,  c("CACL","KCL","H2O"))) %>% 
  group_by(ID) %>% 
  filter(preference == min(preference)) %>% 
  select(-preference)

# A tibble: 3 x 2
# Groups:   ID [3]
     ID method
  <dbl> <fct> 
1     1 CACL  
2     2 KCL   
3     3 H2O