无法通过 python 找到跨度 class

Question

I have a span class attribute which I need to click and pass value to it.

Below is my span class:

<span class="input-group-addon-transparent icon-search sysparm-search-icon"></span>

Please do help me out. Thanks in Advance.

Answer 1

Without knowing the full HTML of the site you can get the first span which matches those classes by using find_element_by_css_selector :

selector = "span.input-group-addon-transparent.icon-search.sysparm-search-icon"
element = driver.find_element_by_css_selector(selector)
element.click()
element.sendKeys("value")

Or waiting for clickable state:

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

selector = "span.input-group-addon-transparent.icon-search.sysparm-search-icon"
element = WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, selector)))
element.sendKeys("value")

Where driver is your Selenium webdriver object

Answer 2

You case use class name to get that webelement.

 webele=  driver.find_element_by_class_name("input-group-addon-transparent icon-search sysparm-search-icon")
webele.click();
webele.sendkeys("any string/number")

or

driver.find_element_by_xpath("//*[contains(@class,'search-icon')]

//and then rest of the code

Use web driver wait before clicking on button

WebDriverWait(driver, 10).until(
    EC.element_to_be_clickable((By.XPATH, "XPATH")) 

Answer 3

Find the xpath of the span using any browser console then try using this code below to click and pass the value to it

span = find_element_by_xpath('''the x_path of the class''').click()
span.sendKeys('''value to be passed''')